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9x^2+12x-672=0
a = 9; b = 12; c = -672;
Δ = b2-4ac
Δ = 122-4·9·(-672)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-156}{2*9}=\frac{-168}{18} =-9+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+156}{2*9}=\frac{144}{18} =8 $
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